中文说明：考虑 16QAM 通信系统。信息速率是 2 Mb/s，载波频率是 12 GHz。 假设完美的同步。a） 模拟系统如果渠道是 awgn 信道下和绘制的误码率的系统与 Eb/号与您获得理论结果对比。b) 考虑到 (15，11) 明码。此代码应用到上述系统。与您获得理论结果对比。c） 模拟的未编码的系统，如果我们有多普勒蔓延，由于移动的运动在通道。模拟和绘制最大系统的误比特率移动速度 42.3 公里/小时。没有均衡器用于在系统中。d） 应用编码成系统的部分 (c) (b) 部分。模拟系统和讨论的结果。e） 设计的交织器系统的部分 (d) 改善编码的性能结果。模拟系统。
English Description：
Considered a 16QAM communication system. The information rate is 2 Mb/s and thecarrier frequency is 12 GHz. Assume perfect synchronization.a) Simulated the system if the channel is AWGN and drawn bit error rate of the systemversus Eb/No. Compared the results with what you obtain in theory.b) Considered (15,11) Hamming code. Applied this code into the above system.Compared the results with what you obtain in theory.c) Simulated uncoded system if we have a Doppler Spread due to mobile movementin the channel. Simulate and draw the bit error rate of the system for maximummobile speed 42.3 Km/Hour. No equalizer is used in the system.d) Applied coding of part (b) into the system of part (c). Simulated the system anddiscuss the results.e) Designed an interleaver for the system of part (d) to improve the coded performanceresults. Simulated the system.